sintheta cos(90^(@)-theta)+costhetasin(90-theta)=sin theta *sintheta+costheta*costheta= sin^(2)theta+cos^(2)theta=1.
Simplify Cos theta/sin(90-theta)+cos(90-theta)/sec(90-theta)-3tan square 30 degrees
Why does cos(90 - x) = sin(x) and sin(90 - x) = cos(x)?
Write the value of sintheta cos(90^(@)-theta)+costheta sin(90^(@)-the
Prove that : (sinthetacos(90^0-theta)costheta)/(sin(90^0-theta))+(cost
Evaluate : sin{theta}cos{theta}-cfrac{sin{theta}cos{(90^o-theta)}cos{theta }}{sin{(90^o-theta)}}-cfrac{cos{theta}sin{(90^o-theta)}sin{theta}}{cosec{(90 ^o-theta)}}.
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Sin theta by sin 90 minus theta + cos theta by cos 90 minus theta is equal to sec 90 minus theta into cosec
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